a basketball scout randomly selected 144 players and timed howlong eah player took to perform a certain drill. the times in thissample were distributed with a mean of 8 minutes. the populationstandard deviation was known to be 3 minutes.

(a) find the critical value for a 95% confidence interval forthe population mean of drill times.
(b) using the 95% confidence interval,estimate the populationmean of drill times.

Formula for 95% confidence interval:

CI95 = mean ± 1.96 (sd/√n)
...where ± 1.96 represents the 95% interval using a z-table.

With your data:
CI95 = 8 ± 1.96 (3/√144)

Finish the calculation.

I hope this helps.

no

We construct a new variable,

Z = (M - m) / [3 / sqrt(144)] = = 4 (M - m)

which then obeys the standard normal distribution.

We are looking for a value z such that P(-z < Z < z) = 0.95. To find this value using the table, we first use the symmetry of the standard normal distribution about its (zero) mean to write:

0.95 = P(-z < Z < z) = 2 P(0 < Z < z) = 2 [P(Z < z) - P(Z <= 0)] = 2 [P(Z < z) - 0.5] = 2 P(Z<z) - 1,

so P(Z < z) = 1.95 / 2 = 0.9750, which gives us the estimate z = 1.96.

Therefore, the confidence interval for M is [m - z/4, m + z/4] = [7.51, 8.49].

B. Not sure how to do the said "estimate." If we take the midpoint of the confidence interval as the estimate, we end up with M = m. A more pessimistic estimate would be closer to 7.51 than to 8.49.

To find the critical value for a 95% confidence interval for the population mean of drill times, we need to find the z-value associated with a 95% confidence level.

(a) Finding the critical value:
Step 1: Determine the confidence level. In this case, it is 95%.
Step 2: Convert the confidence level into a significance level α (alpha). Since the confidence level is 95%, the significance level is 1 - 0.95 = 0.05.
Step 3: Look up the z-value for the significance level α/2 (two-tailed test). In this case, α/2 = 0.05/2 = 0.025. The z-value for a significance level of 0.025 is approximately 1.96.

Therefore, the critical value for a 95% confidence interval for the population mean is 1.96.

(b) Using the 95% confidence interval, estimating the population mean of drill times:
To estimate the population mean, we can use the formula:

Confidence Interval = Sample Mean ± (Critical Value * Standard Error)

The standard error can be calculated using the formula:

Standard Error = (Population Standard Deviation) / square root of (Sample Size)

In this case, the sample size is 144, the population standard deviation is 3, and the critical value is 1.96.

Standard Error = 3 / √144 = 3 / 12 = 0.25

Now, substitute the values into the confidence interval formula:

Confidence Interval = 8 ± (1.96 * 0.25)

Lower Bound = 8 - (1.96 * 0.25) = 7.51
Upper Bound = 8 + (1.96 * 0.25) = 8.49

Therefore, using the 95% confidence interval, the estimated population mean of drill times is between 7.51 minutes and 8.49 minutes.