if the tall f1 generation of pea plants are allowed to self pollinate, the offspring will have this ratio for tall and short?
PLEASE HELP ME!! I HAVE A FINAL AND I NEED HELP!!!
What are your choices?
Use a punnett square to make your choice.
http://www.google.com/search?client=safari&rls=en&q=punnett+square&ie=UTF-8&oe=UTF-8
i know how to do a punnett square but i have no answer choices. that's why i don't know the answer!
To determine the ratio of tall and short offspring in the F2 generation of self-pollinating tall F1 generation pea plants, you can use the principles of Mendelian genetics.
In this case, we need to know the genotypes of the tall and short plants in the F1 generation. Assuming that the tall trait is dominant and the short trait is recessive, the genotypes of the tall plants would be Tt (one copy of the tall allele), while the short plants would be tt (two copies of the short allele).
When the F1 generation self-pollinates, each tall plant has a 50% chance of passing on the tall allele (T) to its offspring and a 50% chance of passing on the short allele (t). This means that if we consider a Punnett square, the possible genotypes for the F2 generation are:
- TT: 25% chance
- Tt: 50% chance
- tt: 25% chance
Now, let's translate these genotypes into phenotypes. Remember, the tall phenotype is dominant and the short phenotype is recessive. So, the tall plants in the F2 generation will have both the genotypes TT and Tt, while the short plants will have the genotype tt.
Therefore, the ratio of tall to short plants in the F2 generation would be 3:1 (75% tall plants and 25% short plants).
In conclusion, if the tall F1 generation of pea plants are allowed to self-pollinate, the offspring in the F2 generation will have a ratio of 3 tall plants to 1 short plant.