Solve the following pls. Calculate the number of grams in these quantities:

1. 0.0600 mol HC2H302
2. 4.50 x10^21 molecules glucose C6H2O6

figure the mole mass of each

mass=numbermoles*molmass
or
mass=numbermolecules*molmass/avagradros number

1. Each mole of HC2H302

has a mass of 60.0 g
Multiply that by 0.06 mole for the answer.

2. That number of molecules is
4.5*10^21/6.02*10^23 = 7.48*10^-3 moles
(You get that by dividing by Avogadro's number)
Each mole has a mass of 110 g. (You get that from the compound formula)
That would be 0.823 g

To calculate the number of grams in a given quantity, we need to use the molar mass of the compound. The molar mass is the mass of one mole of a substance, expressed in grams per mole (g/mol).

To solve both problems, we will follow these steps:
1. Write down the given quantity.
2. Determine the molecular formula of the compound.
3. Look up the molar mass of the compound.
4. Use the given quantity and the molar mass to calculate the number of grams.

Let's apply these steps to the given quantities:

1. 0.0600 mol HC2H302:
- Given quantity: 0.0600 mol
- Molecular formula: HC2H302
- Molar mass: To calculate the molar mass of HC2H302, we add the atomic masses of each element in the compound: H (1.01 g/mol) × 4 + C (12.01 g/mol) × 2 + O (16.00 g/mol) × 2 = 60.05 g/mol
- Calculation: 0.0600 mol × 60.05 g/mol = 3.60 grams

Therefore, there are 3.60 grams in 0.0600 mol of HC2H302.

2. 4.50 x 10^21 molecules glucose C6H12O6:
- Given quantity: 4.50 x 10^21 molecules
- Molecular formula: C6H12O6
- Molar mass: To calculate the molar mass of C6H12O6, we add the atomic masses of each element: C (12.01 g/mol) × 6 + H (1.01 g/mol) × 12 + O (16.00 g/mol) × 6 = 180.18 g/mol
- Calculation: The given quantity is in terms of molecules, so we need to convert it to moles first. The number of moles of glucose can be found using Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 molecules. Thus, 4.50 x 10^21 molecules ÷ (6.022 x 10^23 molecules/mol) = 7.47 x 10^-3 mol.
- Now we can calculate the grams: 7.47 x 10^-3 mol × 180.18 g/mol = 1.35 grams

Therefore, there are 1.35 grams in 4.50 x 10^21 molecules of glucose (C6H12O6).