A volume of 25.0 mL of 8.0 M acetic acid is diluted with sufficient water to prepare 1.00 liter of solution. What is the concentration of the diluted solution?
molarity1 x volume 1 = molarity 2 x volume 2.
To find the concentration of the diluted solution, we need to use the formula:
C1V1 = C2V2
Where:
C1 - initial concentration of the solution
V1 - initial volume of the solution
C2 - final concentration of the solution
V2 - final volume of the solution
In this case, we can plug in the given values:
C1 = 8.0 M
V1 = 25.0 mL
C2 = ? (what we want to find)
V2 = 1.00 L
First, we need to convert the initial volume from milliliters (mL) to liters (L):
V1 = 25.0 mL = 0.025 L
Now we can plug the values into the formula and solve for C2:
(8.0 M)(0.025 L) = C2(1.00 L)
To isolate C2, we divide both sides of the equation by (1.00 L):
(8.0 M)(0.025 L) / (1.00 L) = C2
C2 = 0.2 M
Therefore, the concentration of the diluted solution is 0.2 M.