Please help with this problem, not sure calculate it.
Consider the standard normal distribution and find P(-1.5 < Z < 2.35).
Look up a normal distribution table, such as:
http://www.math.unb.ca/~knight/utility/NormTble.htm
Look up P(Z<2.35), which gives you 0.9906.
We now need to subtract P(Z<-1.5) to get
P(-1.5<Z<2.35).
For this, we need to make use of the fact that the normal distribution is symmetrical about Z=0, hence
P(Z<-1.5)=P(Z>+1.5)=1-P(Z<+1.5)=1-0.9332=0.0668.
So
the required probability
P(-1.5<Z<2.35)=0.9906-0.0668=0.9238
Check my arithmetic.