please help having difficulty with this problem.
It was noted that 40% of the people in Dallas read the morning newspaper. A random sample of 18 people is selected from the city.
On average, how many people would you expect to read the morning newspaper in a sample of 18?
mean = np = 18 * .40 = ?
I'll let you finish the calculation.
To find the average number of people who would be expected to read the morning newspaper in a sample of 18 people, we can use the concept of expected value.
The expected value is calculated by multiplying each possible outcome by its probability and summing them up.
In this case, we know that 40% of people in Dallas read the morning newspaper. Therefore, the probability of an individual person in the sample reading the newspaper is 40% or 0.4.
To find the average for a sample of 18 people, we multiply the probability (0.4) by the sample size (18):
Expected value = Probability * Sample Size
Expected value = 0.4 * 18
Calculating this expression, we get:
Expected value = 7.2
Therefore, on average, we would expect 7.2 people to read the morning newspaper in a sample of 18 people.