math

Calculat the absolute value of:
4-{x-3}=0

PS. The brackets are supposed to be the straight lines for the absolute symbols.

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1. who are all these people that can't find the "|" key? It's shift-\ on every keyboard I've seen.

4-|x-3| = 0
if (x-3) > 0, |x-3| = x-3 and we have
4-(x-3) = 0
4-x+3 = 0
7-x = 0
x = 7

if (x-3) < 0, |x-3| = -(x-3) = 3-x
4-(3-x) = 0
1+x = 0
x = -1

Note that sometimes there are unusable solutions, as in some case where you have

if (x+3) > 5
and you end up with a "solution" of x = -2
which does not satisfy the condition.

In this problems, the solutions obeyed the conditions.

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posted by Steve
2. In order to void the absolute value bars, it needs to stand by itself.

So 4=|x-3|

Now get rid of the value bars and you get:

7 = x

Plug it in and see !

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posted by Joey

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