Write the equation of the line (in slop/intercept form) that has a slop of 7 and goes through the point (6,4).
let the equation be y = 7x + b
but (6,4) lies on it , so
4 = 7(6) + b
b = -38
y = 7x - 38
To find the equation of a line in slope-intercept form (y = mx + b), where m represents the slope and b represents the y-intercept, you can use the given slope and a point on the line.
Given that the slope is 7 and the line passes through the point (6, 4), we can substitute these values into the slope-intercept form equation to find the y-intercept.
Start by substituting the values:
4 = 7(6) + b
Next, simplify the equation:
4 = 42 + b
Now, isolate the variable b by subtracting 42 from both sides:
4 - 42 = b
-38 = b
The equation of the line, in slope-intercept form (y = mx + b), is:
y = 7x - 38