The population of town A increases from 1,346 to 1,500. In the same period, the population of town B increases from 1,546 to 1,800.

a. Find the percent of increase in population for town A and for town B.
b. Which town had the greater percent of increase?

Town A:

1500 - 1346 = 154

154 / 1346 = 0.114 = 11.4%

Figure out the increase for Town B the same way.

Eric, you take the population each town went up to, subtract it with the original population, then divide your answer with the original population, and that is your percentage. Hope that helps bud :)

So you would take 1,800-1,546. whatever you get for that, divide it by 1.546. then whatever you get is your percentage.

i got it wrong

Could You Help Me ?

To find the percent increase in population for each town, we can follow a simple formula:

Percent Increase = ((New Value - Old Value) / Old Value) * 100

a. Let's calculate the percent increase for town A and town B:

Percent increase for town A = ((1,500 - 1,346) / 1,346) * 100
= (154 / 1,346) * 100
≈ 11.44%

Percent increase for town B = ((1,800 - 1,546) / 1,546) * 100
= (254 / 1,546) * 100
≈ 16.43%

b. Since the percent increase for town B (16.43%) is greater than the percent increase for town A (11.44%), town B had the greater percent of increase in population.

no it will be 16.4% that's pretty easy to figure out.

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So it would be 164.9%???