A baby sitter pushing a stroller starts from
rest and accelerates uniformly at a rate of
0.770 m/s
2
.
What is the velocity of the stroller after it
has traveled 5.94 m?
Answer in units of m/s
Vf^2=Vi^2+2ad
solve for Vf
To find the velocity of the stroller after it has traveled 5.94 m, we can use the formula for uniform acceleration:
v^2 = u^2 + 2as
where v is the final velocity, u is the initial velocity (in this case, 0 m/s since the stroller starts from rest), a is the acceleration (0.770 m/s^2), and s is the displacement (5.94 m).
Let's plug in the values:
v^2 = 0^2 + 2 * 0.770 * 5.94
v^2 = 0 + 9.6348
v^2 = 9.6348
To find the velocity v, we take the square root of both sides of the equation:
v = √9.6348
v ≈ 3.106 m/s
Therefore, the velocity of the stroller after it has traveled 5.94 m is approximately 3.106 m/s.
To find the velocity of the stroller after it has traveled 5.94 m, we can use the kinematic equation:
v^2 = u^2 + 2as
where:
v = final velocity
u = initial velocity (in this case, 0 m/s as it starts from rest)
a = acceleration (0.770 m/s^2)
s = distance traveled (5.94 m)
First, let's find the final velocity squared (v^2):
v^2 = 0^2 + 2 * 0.770 m/s^2 * 5.94 m
v^2 = 0 + 11.5132 m^2/s^2
Now we can take the square root of v^2 to find the velocity (v):
v = √(11.5132 m^2/s^2)
v ≈ 3.39 m/s
Therefore, the velocity of the stroller after it has traveled 5.94 m is approximately 3.39 m/s.