How many grams of water can be formed from 10 grams of oxygen?
To determine the number of grams of water that can be formed from 10 grams of oxygen, we need to use the balanced chemical equation for the formation of water:
2H₂ + O₂ → 2H₂O
From the equation, we can see that 1 mole of O₂ reacts with 2 moles of H₂O.
To calculate the number of moles of O₂ in 10 grams, we need to divide the given mass by the molar mass of oxygen, which is approximately 32 grams per mole.
moles of O₂ = mass of O₂ / molar mass of O₂
= 10 grams / 32 grams per mole
= 0.3125 moles of O₂
Now, we can determine the moles of water formed from the moles of oxygen by using the mole ratio of O₂ to H₂O, which is 1:2.
moles of H₂O = moles of O₂ × (2 moles of H₂O / 1 mole of O₂)
= 0.3125 moles of O₂ × 2
= 0.625 moles of H₂O
Lastly, we can find the mass of water formed by multiplying the moles of water by its molar mass, which is approximately 18 grams per mole.
mass of H₂O = moles of H₂O × molar mass of H₂O
= 0.625 moles of H₂O × 18 grams per mole
= 11.25 grams of H₂O
Therefore, 10 grams of oxygen can produce approximately 11.25 grams of water.