How do I find the y value for which the following problem is undefined?
(4y^3-8y)/(y^2-2y)
Find the y values for which the denominator is zero. There are two of them, 0 and 2
Actually, the fraction is well behaved even in the limiting cases, because
(4y^3-8y)/(y^2-2y) = 4y
thanks, that helped a lot!!
To find the y value for which the given problem is undefined, you need to identify the values of y that would make the denominator equal to zero. This is because division by zero is undefined.
In the given problem, the denominator is (y^2 - 2y). To find when this expression equals zero, you can set the denominator to zero and solve for y:
y^2 - 2y = 0
To solve this quadratic equation, you can factor out y:
y(y - 2) = 0
To make the expression equal to zero, either y = 0 or (y - 2) = 0.
So, the values of y for which the problem is undefined are:
y = 0
y = 2