how to solve (3a squared+3a+3)+(15a squared+2a-9) need the steps on how to solve this I have to show all work
= (3a square+3a+3)+ (15a square+5a-9)
= (3ax3a)+3a+3)+(15ax15a)+5a-9))
= 9a sqaure+ 3a+ 3+225a square+ 5a-9
= 9a sqrare+225a square+3a+5a+3-9
=234a square + 8a - 6
Note: 3-9=-6 how?
EXAMPLE: you owed me $9 AND paid me 3. So still you owed me $ 6 and have to pay
adding polynomials (3g squared+2hg)+5g squared+hg-9h squared g) having alot of trouble understanding this I know you have to combine like terms first lost after that need to show all work thanks
To solve the expression (3a^2 + 3a + 3) + (15a^2 + 2a - 9), you can combine like terms and simplify. Here are the steps to solve this expression:
1. Start by adding the like terms within each parentheses:
(3a^2 + 3a + 3) + (15a^2 + 2a - 9)
= (3a^2 + 15a^2) + (3a + 2a) + (3 - 9)
= 18a^2 + 5a - 6
2. Now you have a simplified expression: 18a^2 + 5a - 6.