H2 + I2 -> 2Hl

1.2 mol of hydrogen gas reacts with 1.0 mol of iodine vapour, after 5 minutes 0.6 mol of iodine remained.
A) calculate the number of moles of hydrogen that have not reacted after 5 minutes.
B) calculate the number of moles of hydrogen iodide that have been made after 5 minutes.
please help me

............H2 + I2 ==> 2HI

I...........1.2..1.0......0
C...........-x.....-x.....2x
E................0.6........

I2 reacted must be 1.0-x = 0.6 and solve for x.
Then E for H2 must be 1.2-x = ?
Then HI must be 2x.

To answer these two questions, we will use the balanced chemical equation and the information given about the reaction.

The balanced chemical equation is: H2 + I2 -> 2HI

First, let's calculate the number of moles of hydrogen that have reacted after 5 minutes.

Given:
- Initial moles of hydrogen (H2) = 1.2 mol
- Moles of iodine (I2) = 1.0 mol
- Moles of iodine left after 5 minutes = 0.6 mol

From the balanced equation, we see that the stoichiometric ratio between hydrogen and iodine is 1:1. This means that for every 1 mole of hydrogen reacted, 1 mole of iodine will also react.

Now, let's calculate the moles of hydrogen that have reacted after 5 minutes using the given information:

Initially, we have 1.0 mol of iodine (I2), and after 5 minutes, 0.6 mol of iodine is left. This means that 0.4 mol of iodine has reacted.

Since the stoichiometric ratio between hydrogen and iodine is 1:1, 0.4 mol of hydrogen must have also reacted.

Therefore, the number of moles of hydrogen that have not reacted after 5 minutes is:
Initial moles of hydrogen - moles of hydrogen reacted
= 1.2 mol - 0.4 mol
= 0.8 mol

So, the answer to part A is that there are 0.8 moles of hydrogen that have not reacted after 5 minutes.

Now, let's move on to part B and calculate the number of moles of hydrogen iodide (HI) that have been made after 5 minutes.

From the balanced equation, we see that the stoichiometric ratio between hydrogen and hydrogen iodide is 1:2. This means that for every 1 mole of hydrogen reacted, 2 moles of hydrogen iodide will be produced.

We have already calculated that 0.4 moles of hydrogen have reacted. Therefore, the moles of hydrogen iodide formed will be twice that value.

Moles of hydrogen iodide formed = 2 x moles of hydrogen reacted
= 2 x 0.4 mol
= 0.8 mol

So, the answer to part B is that 0.8 moles of hydrogen iodide have been made after 5 minutes.