Graph the solution set on a number line :
3x+4>-8
3x + 4 > -8.
3x > -8 -4
3x > -12
X > -4.
Locate -4 on a number line, and draw a circle around it. Then draw a st. line
from the circle with the arrow pointing to the right. This means that the solution set is all real values greater
than -4. In other words, the solution set is all real values to the right of
-4.
To graph the solution set of the inequality 3x + 4 > -8 on a number line, you need to follow these steps:
Step 1: Solve the inequality for x.
3x + 4 > -8
Subtract 4 from both sides of the inequality:
3x > -12
Divide both sides of the inequality by 3 (since coefficient is positive, no change in direction):
x > -4
Step 2: Plot the solution on the number line.
Start by marking a point on the number line, which represents -4 (inclusive or exclusive, depending on the inequality). Since the inequality is x > -4, the point at -4 will be an open circle (not filled in).
Then, draw an arrow pointing to the right of the number line, indicating that all values greater than -4 are included in the solution set.
Step 3: Label the graph.
You can label the open circle at -4 with an empty circle or an "o" to signify that it is not included in the solution set.
Your graph should look like this:
```
-4
o--------->
```
This represents all the values of x that satisfy the inequality 3x + 4 > -8.