physics

An object is placed 3cm in front of a diverging lens of focal length of 6cm. the heihgt of the object is 1.5 cm. calculate the image distance and height

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asked by hunar
  1. -1/6-1/3=-1/2
    image distance=-2

    hi/ho=-di/do
    hi/1.5=-(-2)/3
    hi=(2/3)x(3/2)
    hi=1

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    posted by pking
  2. i want to know the formula according to conventions as i saw two different systems as i studied.

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    posted by hunar
  3. For convex and concave lens and for concave and convex mirror
    the formula is

    1/ di + 1/do = 1/f

    m = hi/ho = - di /do


    Note that different conventions are in practice .

    Accordingly the formula will change .

    For the above formula the following sign conventions are used.

    • f is + if the lens is a double convex lens (converging lens)
    • f is - if the lens is a double concave lens (diverging lens)
    • di is + if the image is a real image and located on the opposite side of the lens.
    • di is - if the image is a virtual image and located on the object's side of the lens.
    • hi is + if the image is an upright image (and therefore, also virtual)
    • hi is - if the image an inverted image (and therefore, also real)
    =================================

    For concave and convex mirror
    • f is + if the mirror is a concave mirror
    • f is - if the mirror is a convex mirror
    • di is + if the image is a real image and located on the object's side of the mirror.
    • di is - if the image is a virtual image and located behind the mirror.
    • hi is + if the image is an upright image (and therefore, also virtual)
    • hi is - if the image an inverted image (and therefore, also real)

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    posted by justiin

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