physics

An object is placed 3cm in front of a diverging lens of focal length of 6cm. the heihgt of the object is 1.5 cm. calculate the image distance and height

1. 👍 0
2. 👎 0
3. 👁 95
1. -1/6-1/3=-1/2
image distance=-2

hi/ho=-di/do
hi/1.5=-(-2)/3
hi=(2/3)x(3/2)
hi=1

1. 👍 0
2. 👎 0
posted by pking
2. i want to know the formula according to conventions as i saw two different systems as i studied.

1. 👍 0
2. 👎 0
posted by hunar
3. For convex and concave lens and for concave and convex mirror
the formula is

1/ di + 1/do = 1/f

m = hi/ho = - di /do

Note that different conventions are in practice .

Accordingly the formula will change .

For the above formula the following sign conventions are used.

• f is + if the lens is a double convex lens (converging lens)
• f is - if the lens is a double concave lens (diverging lens)
• di is + if the image is a real image and located on the opposite side of the lens.
• di is - if the image is a virtual image and located on the object's side of the lens.
• hi is + if the image is an upright image (and therefore, also virtual)
• hi is - if the image an inverted image (and therefore, also real)
=================================

For concave and convex mirror
• f is + if the mirror is a concave mirror
• f is - if the mirror is a convex mirror
• di is + if the image is a real image and located on the object's side of the mirror.
• di is - if the image is a virtual image and located behind the mirror.
• hi is + if the image is an upright image (and therefore, also virtual)
• hi is - if the image an inverted image (and therefore, also real)

1. 👍 0
2. 👎 0
posted by justiin

Similar Questions

1. physics

An object is placed 3cm in front of a diverging lens of focal length of 6cm. the heihgt of the object is 1.5 cm. calculate the image distance and height of the image.

asked by hunaa on December 11, 2012
2. physics

An object is placed 3cm in front of a diverging lens of focal length of 6cm. the heihgt of the object is 1.5 cm. calculate the image distance and height of the image

asked by hunaa physics on December 11, 2012
3. Physics

A lighted candle is placed 38 cm in front of a diverging lens. The light passes through the diverging lens and on to a converging lens of focal length 10 cm that is 5 cm from the diverging lens. The final image is real, inverted,

asked by Ali on August 3, 2015
4. AP Physics B

An object is 21 cm in front of a diverging lens that has a focal length of -10 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 1.5?

asked by Alexis on March 15, 2013
5. Physics

An object is 14 cm in front of a diverging lens that has a focal length of -7.9 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 1.9?

asked by Neil on April 14, 2014
6. Physics

An object is placed 11.3 cm to the left of a diverging lens of focal length -6.51 cm. A converging lens of focal length 11.6 cm is placed a distance of d to the right of the diverging lens. Find the distance d that places the

asked by Rachel on September 11, 2015
7. Physics

A diverging lens has a focal length of 17.3 cm. An object 1.08 cm in height is placed 184 cm in front of the lens. Locate the position of the image. Answer in units of cm.

asked by Jared on May 31, 2016
8. Physics

An object is placed 30mm in front of a lens. An image of the object is located 90mm behind the lens. a) Is the lens converging or diverging? explain. b) What is the focal length of the lens? c) Draw a diagram with lens at x=0,

asked by Harly on May 30, 2011