SOCl2 + C4H6CaO4 �¨
The chemical equation you provided is not balanced, so we need to balance it first:
First, let's balance the calcium (Ca) atoms. There is one calcium atom on the right side and none on the left side, so we add a coefficient of 1 in front of C4H6CaO4:
SOCl2 + 1C4H6CaO4 ⟶
Next, let's balance the chlorine (Cl) atoms. There are two chlorine atoms in SOCl2, so we need two chlorine atoms on the other side. We can achieve this by adding a coefficient of 2 in front of C4H6CaO4:
SOCl2 + 1C4H6CaO4 ⟶ 2Cl- + 1C4H6CaO4
Now, let's balance the oxygen (O) atoms. There are four oxygen atoms in C4H6CaO4, so we need four oxygen atoms on the other side. We can achieve this by adding a coefficient of 2 in front of SOCl2:
2SOCl2 + 1C4H6CaO4 ⟶ 2Cl- + 1C4H6CaO4
Finally, let's balance the sulfur (S) atoms. There are two sulfur atoms on the left side and none on the right side. We can balance this by adding a coefficient of 2 in front of Cl-:
2SOCl2 + 1C4H6CaO4 ⟶ 2Cl- + 1C4H6CaO4 + 2S
Now, the equation is balanced:
2SOCl2 + 1C4H6CaO4 ⟶ 2Cl- + 1C4H6CaO4 + 2S
Note that the arrow represents the chemical reaction, where the reactants (SOCl2 and C4H6CaO4) are converted into the products (Cl-, C4H6CaO4, and S).
If you have any further questions, feel free to ask!