N2O5 + H2O ---> 2HNO3
The reaction is first order in each reactant. Write the rate law for the reaction
my guess
rate= k[N2O5]^1[H2O]^1
I agree. Of course the ^1 is not necessary.
Your guess is correct! The rate law for the given reaction, assuming it is first order in each reactant, can be written as follows:
rate = k [N2O5]^1 [H2O]^1
In this rate law, the exponents are determined by the reaction order with respect to each reactant. Since both N2O5 and H2O have a reaction order of 1, they are raised to the power of 1 in the rate law.
The rate constant "k" represents the proportionality constant between the rate of the reaction and the concentrations of the reactants. The specific value of "k" would need to be determined experimentally.
So, the rate law you wrote reflects that the rate is directly proportional to the concentrations of N2O5 and H2O, each raised to the power of 1.
You are correct! The rate law for the reaction N2O5 + H2O -> 2HNO3 is indeed:
rate = k[N2O5]^1[H2O]^1
The exponent of 1 for each reactant indicates first-order kinetics, where the rate of the reaction is directly proportional to the concentration of each reactant raised to the power of their respective coefficients in the balanced equation. The constant k is the rate constant, which determines the rate of the reaction at a specific temperature.