hey guys need some help here!!!
if 0.250mol of CO and 0.250mol of H2O were combined in a 125mL flask and the reaction allowed to reach equilibrium . Kc= 1.56. write the equ expression and calculate each substance
Co(g) +H2O(g) .... Co2(g) +H2(g)
how to work out (x)(x)
-------- = 1.56
( 2-x)(2-x)
............CO + H2O ==> CO2 + H2
I...........2....2........0.....0
C...........-x...-x.......x.....x
E...........2-x..2-x......x.....x
Kc = (CO2)(H2)/(CO)(H2O)
1.58 = (x)(x)/(2-x)(2-x)
The right side is a perfect square so take the square root of each side.
1.256 = (x)/(2-x)
Solve for x
Sure! To write the equilibrium expression, we need to look at the balanced chemical equation for the reaction:
Co(g) + H2O(g) ⇌ CO2(g) + H2(g)
The equilibrium expression is written using the concentrations of the products and reactants. The coefficients of the balanced equation represent the stoichiometric ratios between them:
Kc = [CO2] * [H2] / [CO] * [H2O]
Now, let's calculate the concentrations of each substance in the equilibrium mixture.
Given:
- 0.250 mol of CO
- 0.250 mol of H2O
- 125 mL flask
To determine the concentrations, we need to convert the amount in moles to concentration in mol/L (M).
Concentration (M) = moles / volume (L)
For carbon dioxide (CO2):
CO2: Since it is a product, we need to calculate the concentration based on the amount that forms. From the reaction, we see that 1 mol of CO2 is formed for every 1 mol of CO. So, the concentration of CO2 will also be 0.250 M.
For hydrogen (H2):
H2: Similarly, it is a product in a 1:1 ratio with H2O. Therefore, the concentration of H2 will also be 0.250 M.
For carbon monoxide (CO):
CO: Since we're starting with 0.250 mol of CO and given that the total volume is 125 mL (0.125 L), we can calculate the concentration:
Concentration (CO) = 0.250 mol / 0.125 L = 2.0 M
For water (H2O):
H2O: Given that we have 0.250 mol of H2O and a total volume of 0.125 L, we can calculate the concentration:
Concentration (H2O) = 0.250 mol / 0.125 L = 2.0 M
So, the concentrations of each substance in the equilibrium mixture are:
[CO] = 2.0 M
[H2O] = 2.0 M
[CO2] = 0.250 M (from the reaction)
[H2] = 0.250 M (from the reaction)
I hope that helps! Let me know if you have any further questions.