The equation for photon energy, , is

where = 6.626×10−34 (Planck's constant) and = 3.00×108 (the speed of light).
What is the wavelength, , of a photon that has an energy of = 3.99×10−19 ?
How do go about solving this? I multipled the constant w/ the speed of light and divided it by the proton energy but its not correct

I've written this more than once but I'll try again. We need for you to show your work. Although it appears your method is right, you may not have substituted, multiplied, or divided correctly. Include the answer you obtained from your work.

To find the wavelength (λ) of a photon with a given energy (E), you can use the equation:

E = hc/λ

Where:
- E is the energy of the photon
- h is Planck's constant (6.626×10^-34 J·s)
- c is the speed of light (3.00×10^8 m/s)
- λ is the wavelength of the photon

To solve the equation for λ, rearrange it to isolate λ on one side:

λ = hc/E

Now you can substitute the given values into the equation:

λ = (6.626×10^-34 J·s)(3.00×10^8 m/s)/(3.99×10^-19 J)

Perform the multiplication and division:

λ = (1.99×10^-25 J·m)/(3.99×10^-19 J)

Then, you can simplify the expression by dividing the numerator and denominator by the same power of 10 to eliminate the negative exponent:

λ = (1.99/3.99) × 10^(-25+19) m

λ = 0.498 × 10^-6 m

Finally, convert the scientific notation to decimal form:

λ = 4.98 × 10^-7 m

So, the wavelength of the photon with an energy of 3.99×10^-19 J is approximately 4.98 × 10^-7 m.