Graph each compound inequality.
f>3 or f< -2
Which one do I graph? Im confused.....
I think that you graph both; if you were asked to graph f>3 AND f< -2, there would be nothing to graph, because there is no intersection of the graphs. But because the selector is OR, you graph all the points for which f>3 (y > 3) or f<-2 (y<-2)
To graph the compound inequality "f > 3 or f < -2," you will need to graph both inequalities separately and then combine their solutions.
Let's start by graphing the inequality f > 3:
1. Draw a number line and label it with values.
2. Mark a vertical dotted line at the value f = 3 to indicate that f is not included in the solution.
3. Shade the region to the right of the dotted line to represent all values of f greater than 3.
Next, let's graph the inequality f < -2:
1. Draw a number line and label it with values.
2. Mark a vertical dotted line at the value f = -2 to indicate that f is not included in the solution.
3. Shade the region to the left of the dotted line to represent all values of f less than -2.
Now, to determine the combined regions, look for where the shaded regions overlap or unite. In this case, since it's an "or" inequality, you will take the union of both shaded regions.
Combining the shaded regions from the two inequalities, the final graph will show all values of f that are either greater than 3 or less than -2.