AP PHYSICS HELP

A 1.47 x 10^6 kg steel hull has a base that is 2.5 x 10^3 m^2 in area. If it is placed in sea water (density= 1025 kg/m^3), how deep does the hull sink?

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asked by JOHN
  1. if the hull sinks x meters, it displaces 2500x m^3 of water.

    1m^3 of water weighs 1000kg so

    2500*x*1025 = 1.47*10^6
    x = 0.573m

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    posted by Steve
  2. Thanx!!!!

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    posted by JOHN

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