find the equation to the line tangent to y=(x+3)^(1/3) at x=-3.
dy/dx = (1/3)(x+3)^-(2/3)
slope at x = -3 has 0 in the denominator so the line is vertical
equation of that line is
x = -3
period
slope at x = -3 has 0 in the denominator so the line is vertical
equation of that line is
x = -3
period