Are you available to help for a few more min.

I am back. Been gone about two hours. What is it you don't understand about the former problem?

Honestly I don't know what am I doing wrong or what should i be doing with the previous problem the one about

Direction. Simplify each of the following expressions where possible.

6x^2y^3+9x^2y^3 divided by 3x^2y^2

don't i have to do for the following top numbers of division add the whole numbers then add both x^2 because i have to combine like terms in order to simplify then i have to divide my answer with the what ever is on the bottom of the division. As you can see i am clueless about what to do.

6x^2y^3 + 9x^2y^3 divided by 3x^2y^2

First, factor the numerator. You can take out 3 from the 6 and 9 and you can take out x^2y^3 since that appears in both of the terms added. So the factored numerator will look like this.

The denominator is ok as it is. So the fraction now looks like this.
Three from the bottom goes into the top 15 5 times. x^2 on top and bottom cancel. y^3 on top and y^2 on bottom leaves y on top. The final answer is

Thank you for your explanation I'm going to print your answer to keep it as future reference for when i have test and follow your steps. I have to reread it so i can understand it. I want to really know the material just incase for when i get an exam.All your help is very appreciated.

Actually, I worked it the hard way.
The easier way is to simply add the two number in the numerator. Since both are numbers (one 6 and the other 15) of x^2y^3, we can (without factoring) just add them together to obtain 15x^2y^3.
Then place that over the denominator to get the following:
(15x^2y^3)/(3x^2y^2) and simplify from there as I did above. That saves the factoring step that I used at the beginning.

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