# drbob222

Are you available to help for a few more min.

I am back. Been gone about two hours. What is it you don't understand about the former problem?

Honestly I don't know what am I doing wrong or what should i be doing with the previous problem the one about

Direction. Simplify each of the following expressions where possible.

6x^2y^3+9x^2y^3 divided by 3x^2y^2

don't i have to do for the following top numbers of division add the whole numbers then add both x^2 because i have to combine like terms in order to simplify then i have to divide my answer with the what ever is on the bottom of the division. As you can see i am clueless about what to do.

6x^2y^3 + 9x^2y^3 divided by 3x^2y^2

First, factor the numerator. You can take out 3 from the 6 and 9 and you can take out x^2y^3 since that appears in both of the terms added. So the factored numerator will look like this.
3x^2y^3(2+3)=3x^2y^3(5)=15x^2y^3.

The denominator is ok as it is. So the fraction now looks like this.
(15x^2y^3)/(3x^2y^2)=
Three from the bottom goes into the top 15 5 times. x^2 on top and bottom cancel. y^3 on top and y^2 on bottom leaves y on top. The final answer is
5y.

Thank you for your explanation I'm going to print your answer to keep it as future reference for when i have test and follow your steps. I have to reread it so i can understand it. I want to really know the material just incase for when i get an exam.All your help is very appreciated.

Actually, I worked it the hard way.
The easier way is to simply add the two number in the numerator. Since both are numbers (one 6 and the other 15) of x^2y^3, we can (without factoring) just add them together to obtain 15x^2y^3.
Then place that over the denominator to get the following:
(15x^2y^3)/(3x^2y^2) and simplify from there as I did above. That saves the factoring step that I used at the beginning.

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