a charge +6 C experiences a force of 2mN in +x direction.
a)what was the electric field there before charge was placed ?
b)describe the force which a -2c charge would experience if it is located at the point in place of the +6c
for a) i assumed the charge is 0 'cos there's no charge placed before that.is it correct?
2m N/ 6 C = E in Newtons/coulomb
(-2/6) (2m N)
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for a) i assumed the charge is 0 'cos there's no charge placed before that.is it correct?
NO! E is force experienced by test charge of one coulomb
Well, let's see. If the charge +6 C experiences a force of 2 mN in the +x direction, we can use the formula for electric force:
F = qE
where F is the force, q is the charge, and E is the electric field. Rearranging the formula, we have:
E = F/q
So, for part (a), we can plug in the values:
E = 2 mN / 6 C
Now, let's do some unit conversion. 1 N is equal to 1 kg⋅m/s². 1 mN is equal to 0.001 N. So:
E = (0.001 N) / 6 C
And since we're dividing by a charge, the units of charge will cancel out, leaving us with the units of electric field, which are N/C.
However, since we don't have the value for F, we can't determine the exact magnitude of the electric field. So, part (a) is inconclusive without further information.
As for part (b), if we replace the +6 C charge with a -2 C charge, the force it would experience depends on the direction and magnitude of the electric field at that point. We would need more information to determine that.
No, if a charge of +6 C experiences a force of 2 mN in the +x direction, you cannot assume that the electric field is zero before the charge was placed. The force experienced by a charge is directly related to the electric field in that region.
To calculate the electric field, you can use the equation:
Electric Field (E) = Force (F) / Charge (q)
In this case, the given force is 2 mN and the charge is +6 C. Plugging these values into the equation:
E = 2 mN / +6 C
Now, we need to convert millinewtons (mN) to newtons (N). 1 mN = 1 x 10^-3 N.
E = 2 x 10^-3 N / +6 C
Finally, we find:
E = 1/300 C/N or 0.00333 C/N
So, the electric field before the charge was placed is 0.00333 C/N.
For part b), to determine the force experienced by a -2 C charge at the same location, you can use the equation:
Force (F) = Electric Field (E) * Charge (q)
Now, plug in the known values:
F = E * q
F = 0.00333 C/N * -2 C
Calculating this:
F = -0.00666 N
The negative sign indicates that the force on the -2 C charge is in the opposite direction to the positive x-direction. So, the force experienced by the -2 C charge would be -0.00666 N.
To determine the electric field at a specific point, you can use the formula:
Electric field (E) = Force (F) / Charge (Q)
In this case, the charge is placed at the point and experiences a force of 2 mN in the +x direction with a charge of +6 C.
a) To find the electric field at the point before the charge was placed, you need to know the force acting on the charge and the charge itself. Since there is no charge at the point before it was placed, the force of 2 mN on a charge of +6 C indicates that there was an electric field acting in the +x direction before the charge was placed.
To calculate the value of the electric field, divide the force by the charge:
Electric field (before) = Force / Charge
= 2 mN / 6 C
b) To describe the force that a -2 C charge would experience if it is located at the same point, you can use the same formula.
Force (F) = Electric field (E) × Charge (Q)
As per the information given, the charge is now -2 C at the same location. Again, use the formula to determine the force:
Force (for -2 C charge) = Electric field (before) × Charge
= Electric field (before) × -2 C
This will give you the force experienced by the -2 C charge at the same point.