Physics

Five Forces act on an object:
1. 60 N at 90 degrees
2. 40 N at 0 degrees
3. 80 N at 270 degrees
4. 40 N at 180 degrees
5. 50 N at 60 degrees

What are the magnitude and direction of a sixth force that would produce equilibrium?

1. 👍 0
2. 👎 0
3. 👁 1,032
1. Forces 2 and 4 cancel each other.
Forces 1 and 3 combined are the same as
20 N at 270 degrees. First calculate the resultant. The equilibrant will be the opposite of that.

So, add 20 N at 270 and 50 N at 60.

North direction component = 50sin60 = 43.3
East direction component = -20 + 50cos60 = 5

Magnitude = sqrt[43.3^2 + 5^2] = 43.6 newtons

Direction = 6.6 degrees E of N

For the equilibrant, make that 186.6 degrees

1. 👍 0
2. 👎 0
posted by drwls

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