HCl+CaCO3 --> CaCl+H3O balanced?

No. It is not balanced.

There is no such thing as (neutral) H3O, nor is there any CaCl. The products should be H2O and CaCl2.

How did you get 3 H's in the products with only one H in the reactants? What happened to two of the three O atoms you started out with?

Try again.

Tks. As I thought

To determine if the chemical equation HCl + CaCO3 → CaCl + H3O is balanced, we need to ensure that there is an equal number of each type of atom on both the reactant (left) side and the product (right) side of the equation.

Let's break down each compound into its constituent elements:
Reactants:
- HCl: Hydrogen (H) and Chlorine (Cl)
- CaCO3: Calcium (Ca), Carbon (C), and Oxygen (O)

Products:
- CaCl: Calcium (Ca) and Chlorine (Cl)
- H3O: Hydrogen (H) and Oxygen (O)

Now, let's count the number of each type of atom on both sides of the equation:

Reactants:
- Hydrogen (H): 1 (from HCl) and 3 (from H3O) = total of 4 H atoms
- Chlorine (Cl): 1 (from HCl) and 1 (from CaCl) = total of 2 Cl atoms
- Calcium (Ca): 1 (from CaCO3) = 1 Ca atom
- Carbon (C): 1 (from CaCO3)
- Oxygen (O): 3 (from CaCO3) and 1 (from H3O) = total of 4 O atoms

Products:
- Hydrogen (H): 3 (from H3O) = 3 H atoms
- Chlorine (Cl): 1 (from CaCl) = 1 Cl atom
- Calcium (Ca): 1 (from CaCl)
- Oxygen (O): 1 (from H3O) = 1 O atom

Comparing the number of atoms on each side, the equation is not balanced, as the number of atoms for each element does not match.

To balance the equation, we need to adjust the coefficients (numbers in front of the compounds) to equalize the number of atoms on each side. The balanced equation for the reaction should be:

2HCl + CaCO3 → CaCl2 + H2O

In this balanced equation, there are now 2 HCl molecules on the reactant side, 1 CaCO3 molecule, 1 CaCl2 molecule, and 2 H2O molecules on the product side. This balances the number of atoms for each element on both sides of the equation.