3.54 x 10^2 J of work is done to speed up a 1.22 x 10^2 kg log rolling along the ground. If the log was originlly moving at 2.3 m/s, determine how fast it ends up going.

Added work = (kinetic energy increase)

354 J = (1/2)*122*[Vfinal^2 - 2.3^2]
= 61*Vfinal^2 - 323

Solve for Vfinal, the final velocity