The titration of 25.0 mL of an unknown concentration H2SO4 solution requires 83.6 mL of 0.12 M LiOH solution. What is the concentration of the H2SO4 solution (in M)?
H2SO4 + 2LiOH ==> Li2SO4 + 2H2O
mols LiOH = M x L = ?
mols H2SO4 = 1/2 that.
M H2SO4 = mols H2SO4/L H2SO4. iii
To find the concentration of the H2SO4 solution, we can use the concept of stoichiometry. In this titration, a neutralization reaction occurs between H2SO4 and LiOH, in a 1:2 mole ratio.
First, let's find the moles of LiOH used in the reaction:
moles of LiOH = volume of LiOH solution (in liters) x molarity of LiOH
moles of LiOH = 83.6 mL x 0.12 M = 10.03 mmol
Since the mole ratio between LiOH and H2SO4 is 1:2, we multiply the moles of LiOH by 2 to determine the moles of H2SO4:
moles of H2SO4 = 2 x moles of LiOH
moles of H2SO4 = 2 x 10.03 mmol = 20.06 mmol
Next, we convert the volume of the H2SO4 solution used in the titration to liters:
volume of H2SO4 solution (in liters) = 25.0 mL = 0.025 L
Finally, we can calculate the concentration of the H2SO4 solution by dividing the moles of H2SO4 by the volume of the solution in liters:
concentration of H2SO4 = moles of H2SO4 / volume of H2SO4 solution (in liters)
concentration of H2SO4 = 20.06 mmol / 0.025 L = 802.4 mmol/L
Converting millimoles to moles:
concentration of H2SO4 = 802.4 mmol/L = 0.8024 M
Therefore, the concentration of the H2SO4 solution is 0.8024 M.