How many atoms of carbon are contained in 47.6 g of Al2(CO3)3? The molar mass of Al2(CO3)3 is 233.99 g/mol.
3.68x10^23 C atoms
ratio
sarthak is correct
To find the number of atoms of carbon in 47.6 g of Al2(CO3)3, we need to follow these steps:
Step 1: Calculate the number of moles of Al2(CO3)3.
To do this, divide the given mass (47.6 g) by the molar mass of Al2(CO3)3 (233.99 g/mol):
Number of moles = Mass / Molar mass
Number of moles = 47.6 g / 233.99 g/mol
Step 2: Determine the mole ratio of carbon in Al2(CO3)3.
Looking at the chemical formula Al2(CO3)3, we can see that there are three carbon atoms for every one Al2(CO3)3 formula unit.
Step 3: Calculate the number of moles of carbon.
Multiply the number of moles of Al2(CO3)3 (calculated in Step 1) by the mole ratio of carbon:
Number of moles of carbon = Number of moles of Al2(CO3)3 × Mole ratio of carbon
Number of moles of carbon = (47.6 g / 233.99 g/mol) × (3 mol C / 1 mol Al2(CO3)3)
Step 4: Convert the number of moles of carbon into atoms.
To convert moles to atoms, we multiply the number of moles by Avogadro's number, which is approximately 6.022 × 10^23 atoms/mol:
Number of atoms of carbon = Number of moles of carbon × Avogadro's number
Number of atoms of carbon = (47.6 g / 233.99 g/mol) × (3 mol C / 1 mol Al2(CO3)3) × (6.022 × 10^23 atoms/mol)
Now, let's calculate the number of atoms of carbon:
Number of atoms of carbon = (47.6 g / 233.99 g/mol) × (3 mol C / 1 mol Al2(CO3)3) × (6.022 × 10^23 atoms/mol)
mols Al2(CO3)3 = grams/molar mass
Atoms C = 3x that.
DrBob222 is wrong and you wouldn't ask if you didn't need the answer.
take molar mass of C/molar mass of Al2(CO3)3, multiply that by 47.6 g, and then multiply that by avogadro's number (6.022*10^23) = 1.23*10^23