A balloon is inflaed outdoors on a cold day in lowa at a temperature of -40 c to a volume of 2.00 l. If the pressure remains constant, what is the volume of the same balloon if taken indoors at a temperature of 25 c?

(V1/T1) = (V2/T2)

Remember T must be in kelvin.

To find the volume of the balloon when taken indoors at a temperature of 25 °C, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature, assuming the pressure and moles of the gas remain constant.

Step 1: Convert the temperatures from Celsius to Kelvin.
-40 °C = 233.15 K (convert using the formula K = °C + 273.15)
25 °C = 298.15 K

Step 2: Use Charles's Law formula to find the volume.
V1 / T1 = V2 / T2
V1 = 2.00 L (initial volume at -40 °C)
T1 = 233.15 K (initial temperature at -40 °C)
V2 = ? (volume at 25 °C)
T2 = 298.15 K (temperature at 25 °C)

Using the formula, we can rearrange it to find V2:
V2 = (V1 * T2) / T1

Substituting the values:
V2 = (2.00 L * 298.15 K) / 233.15 K

Calculating:
V2 = 2.560 L

Therefore, the volume of the same balloon when taken indoors at a temperature of 25 °C would be approximately 2.560 liters.

To find the volume of the balloon when taken indoors at a temperature of 25 ºC, you can use Charles' Law. Charles' Law states that at constant pressure, the volume of a gas is directly proportional to its temperature.

First, let's convert the temperatures to Kelvin since temperature in Kelvin is directly proportional to volume. To convert Celsius to Kelvin, you simply add 273.15 to the Celsius temperature.

The initial temperature is -40 ºC, so in Kelvin, it will be:

T1 = -40 ºC + 273.15 = 233.15 K

The final temperature is 25 ºC, so in Kelvin, it will be:

T2 = 25 ºC + 273.15 = 298.15 K

Now we can set up the proportion:

V1/T1 = V2/T2

Where:
V1 = initial volume = 2.00 L
T1 = initial temperature in Kelvin = 233.15 K
V2 = final volume (what we need to find)
T2 = final temperature in Kelvin = 298.15 K

Rearranging the equation to solve for V2:

V2 = (V1 * T2) / T1

Plugging in the values we know:

V2 = (2.00 L * 298.15 K) / 233.15 K

Calculating this gives us:

V2 ≈ 2.56 L

Therefore, the volume of the balloon when taken indoors at 25 ºC will be approximately 2.56 L.