Suppose that absorbances of several solutions were measured at 545 nm. What is the frequency of this wavelength? What is the energy of this wavelength? (h=6.626 times 10^-34J*S)
What is the freq? You got C=2x10^8m/s but you don't have the freq.
Isn't the problem asking for frequency? You use c = f*w to solve for f.
And I don't see anywhere that I have 2E8 m/s.
c = f*w
3E8 = f*545E-9
Solve for f.
Is F=5.55*10^14Hz?
close. I obtained 5.504E14 Hz which I would round to 5.50E14 Hz to three significant figures..
For the energy is it around 3.647x10^-19J? And how did you know that c=3*10^8m/s?
c is the speed of light. Look in your text for a table of physical constants and you will find the speed of light as 299,792,458 m/s which most of us round to 3E8 m/s most of the time.
I found E to be the same number you have.
To calculate the frequency of a wavelength, you can use the formula:
frequency (ν) = speed of light (c) / wavelength (λ)
The speed of light is a constant value of approximately 3 x 10^8 m/s.
First, we need to convert the wavelength from nm (nanometers) to meters. Since 1 meter is equal to 10^9 nm, we divide the wavelength by 10^9 to convert it to meters.
So, the wavelength in meters (λ) = 545 nm / 10^9 = 5.45 x 10^-7 meters.
Next, we can substitute the values into the formula:
frequency (ν) = 3 x 10^8 m/s / 5.45 x 10^-7 meters
Calculating this, we find that the frequency is approximately 5.5 x 10^14 Hz.
To calculate the energy of the wavelength, you can use the equation:
energy (E) = Planck's constant (h) * frequency (ν)
Given that the value of Planck's constant (h) is 6.626 x 10^-34 J·s, we can substitute the frequency we calculated earlier into the equation:
energy (E) = 6.626 x 10^-34 J·s * 5.5 x 10^14 Hz
After performing the calculation, we find that the energy of the wavelength is approximately 3.64 x 10^-19 J.
c = freq x wavelength.
c = 3E8 m/s
freq = ? in Hz.
wavelength = 545 nm x 10^-9 m
For E in J = hc/wavelength.