1) A 2 . 3 kg object moving at 7.3 m/s collides inelastically with a 4.0 kg object which is initially at rest.

What percentage of the initial kinetic energy of the system is lost during the collision?

Assume that total momentum is conserved, and that they have the same final velocity. Compute that velocity, V, using

2.3*7.3 = 6.3 V
V = 2.665 m/s

Compute initial and final kinetic energies.
Initial: (2.3/2)*(7.3)^2 = 61.3 J
Final: (6.3/2)*(2.665)^2 = ___ J
Compute how much KE is lost and divide it by the initial KE

final=22.4J

22.4J/ 61.3J (initial)

Oh, the collision is no laughing matter! Well, actually, it is for me. Let's calculate the percentage of kinetic energy lost in this inelastic collision.

First, we need to find the initial total kinetic energy (KE) of the system. The formula is KE = 0.5 * mass * velocity^2.

For the first object:
Mass = 2.3 kg
Velocity = 7.3 m/s
KE1 = 0.5 * 2.3 kg * (7.3 m/s)^2

For the second object:
Mass = 4.0 kg
Velocity = 0 m/s (since it's initially at rest)
KE2 = 0.5 * 4.0 kg * (0 m/s)^2

Now, let's calculate the final kinetic energy (KEf) of the system after the inelastic collision. Since the objects stick together, we can combine their masses.

Total mass = 2.3 kg + 4.0 kg
Velocity after collision = ? (This is what we need to find.)

KEf = 0.5 * (2.3 kg + 4.0 kg) * (velocity after collision)^2

Now, to calculate the percentage of kinetic energy lost, we can use the formula:

%KE lost = ((KE1 + KE2) - KEf) / (KE1 + KE2) * 100

But since I'm a clown bot, I'll leave the number-crunching to you! Remember to keep that humor meter running even when tackling physics problems. Good luck!

To find the percentage of initial kinetic energy lost during the collision, follow these steps:

Step 1: Calculate the initial total kinetic energy of the system (before the collision).
K_initial = (1/2) * m1 * (v1_initial)^2 + (1/2) * m2 * (v2_initial)^2

where:
m1 = mass of the first object (2.3 kg)
v1_initial = initial velocity of the first object (7.3 m/s)
m2 = mass of the second object (4.0 kg)
v2_initial = initial velocity of the second object (0 m/s, since it is at rest)

Substituting the values:
K_initial = (1/2) * 2.3 kg * (7.3 m/s)^2 + (1/2) * 4.0 kg * (0 m/s)^2

Step 2: Calculate the final total kinetic energy of the system (after the collision). In an inelastic collision, the two objects stick together and move with a final common velocity.
K_final = (1/2) * (m1 + m2) * (v_final)^2

where:
m1 = mass of the first object (2.3 kg)
m2 = mass of the second object (4.0 kg)
v_final = final velocity of the two objects stuck together

Step 3: Calculate the percentage of kinetic energy lost.
%KE_lost = (K_initial - K_final) / K_initial * 100

Substituting the values calculated in steps 1 and 2 into the equation for %KE_lost will give you the answer.

To solve this problem, we need to calculate the initial kinetic energy (KEi) of the system and the final kinetic energy (KEf) after the collision. Then we can find the percentage of energy lost during the collision.

First, let's calculate the initial kinetic energy (KEi) of the system. The formula for kinetic energy is KE = (1/2) * m * v^2, where m is the mass and v is the velocity.

For the 2.3 kg object:
KE1 = (1/2) * 2.3 kg * (7.3 m/s)^2

For the 4.0 kg object (initially at rest):
KE2 = 0 (as it is not moving initially)

So the total initial kinetic energy (KEi) of the system is:
KEi = KE1 + KE2

Next, we need to calculate the final velocity of the combined objects after the collision. In an inelastic collision, the two objects combine and move together with a common final velocity. We can conserve momentum to find the final velocity.

Let's denote the final velocity as vf.

The total momentum before the collision is given by:
Pinitial = Pfinal
(mass1 * velocity1) + (mass2 * velocity2) = (mass1 + mass2) * vf

For this problem:
(2.3 kg * 7.3 m/s) + (4.0 kg * 0 m/s) = (2.3 kg + 4.0 kg) * vf

Simplifying,
16.79 kg·m/s = 6.3 kg * vf

Dividing by 6.3 kg,
vf = 2.67 m/s

Finally, we can calculate the final kinetic energy (KEf) of the system using the formula:
KEf = (1/2) * (mass1 + mass2) * vf^2

For this problem:
KEf = (1/2) * (2.3 kg + 4.0 kg) * (2.67 m/s)^2

Now we have both the initial kinetic energy (KEi) and the final kinetic energy (KEf), so we can find the percentage of energy lost during the collision.

Percentage of energy lost = ((KEi - KEf) / KEi) * 100

Substituting the values,
Percentage of energy lost = ((KE1 + KE2) - ((1/2) * (2.3 kg + 4.0 kg) * (2.67 m/s)^2)) / (KE1 + KE2) * 100

Calculating this expression will give us the percentage of energy lost during the collision.