2 to the 2nd exponet x 3 x5 to the 4th exponent x 8 x 11 to the 2nd exponent is not a prime factoration right? because of the 8 ?

To determine if the expression you provided is a prime factorization, we need to simplify it further.

Let's break it down step by step:

2^2 x 3 x 5^4 x 8 x 11^2.

First, we can simplify 2^2 to get 4.

So the expression becomes:

4 x 3 x 5^4 x 8 x 11^2.

Next, let's simplify 8, which can be expressed as 2^3.

Now, the expression becomes:

4 x 3 x 5^4 x 2^3 x 11^2.

Finally, we can simplify further:

4 x 3 x (2 x 2 x 2) x (5 x 5 x 5 x 5) x (11 x 11).

Multiplying all of these factors together, we get:

4 x 3 x 8 x 625 x 121.

Now, we can calculate the result:

4 x 3 = 12
12 x 8 = 96
96 x 625 = 60,000
60,000 x 121 = 7,260,000.

Therefore, the prime factorization of the original expression is not just one prime number but rather a product of prime factors: 2 x 2 x 2 x 3 x 5 x 5 x 5 x 5 x 11 x 11 = 7,260,000.