How can you prepare 2M of 200 ml HNO3 solution from 63% stock solution of HNO3 which has a density of 1.4 g/ml?

Calculate the molarity of the stock solution.

1.4 g/mL x 1000 mL x 0.63 x (1/molar mass HNO3) = ? M HNO3.
Then use the dilution formula of
c1v1 = c2v2
c = concn
v = volume

Useful

To prepare a 2M HNO3 solution from a 63% stock solution, you need to calculate the appropriate volume of the stock solution needed and then dilute it to the desired concentration. Here's how you can do it step-by-step:

Step 1: Determine the molecular weight of HNO3.
- HNO3 = 1(1) + 1(14) + 3(16) = 1 + 14 + 48 = 63 g/mol

Step 2: Calculate the mass of HNO3 required to prepare 200 ml of a 2M solution.
- Mass = molar concentration × molar mass × volume
- Mass = 2 mol/L × 63 g/mol × 0.200 L = 25.2 g

Step 3: Calculate the volume of the 63% stock solution needed, using the density and mass calculated in the previous step.
- Density = mass / volume
- Volume = mass / density = 25.2 g / 1.4 g/mL = 18 mL (rounded to the nearest whole number)

Step 4: Dilute the 18 mL of the 63% HNO3 stock solution to a final volume of 200 mL to achieve a 2M concentration.
- Add the 18 mL of the stock solution to a volumetric flask or container.
- Gradually add distilled water to reach a final volume of 200 mL.
- Mix well to ensure uniformity.

So, to prepare a 2M HNO3 solution, you need to measure 18 mL of the 63% stock solution and then dilute it to 200 mL with distilled water.

To prepare a 2M HNO3 solution using a 63% stock solution, we will need to calculate the amount of stock solution and the amount of water needed.

Here's how you can do it step by step:

Step 1: Determine the volume of the stock solution needed.
To calculate the volume, use the formula:
Volume = (Desired concentration / Stock solution concentration) * Desired volume
In this case, the desired concentration is 2M, the stock solution concentration is 63%, and the desired volume is 2L (2000 mL).

Volume = (2M / 0.63) * 2000 mL
= (3.17) * 2000 mL
= 6340 mL

Step 2: Convert the volume from milliliters to grams.
To do this, multiply the volume (6340 mL) by the density of the stock solution (1.4 g/mL).

Mass = Volume * Density
Mass = 6340 mL * 1.4 g/mL
= 8876 g

So, you will need 8876 grams of the 63% stock HNO3 solution.

Step 3: Determine the amount of water needed.
To find the amount of water, subtract the mass of the stock solution from the total desired volume.

Volume of water = Desired volume - Volume of stock solution
Volume of water = 2000 mL - 6340 mL
= -4340 mL

Since the volume of water is negative, it means that you don't need any additional water for dilution. This is because the stock solution is concentrated enough to achieve the desired concentration of 2M.

In summary, to prepare 2M HNO3 solution from a 63% stock solution with a density of 1.4 g/mL, you will need 8876 grams of the stock solution without any additional water.