For nine months of the year farmers tended their crops. What fraction of a year did they farm? Reduce the fraction to its lowest terms.

9/12 = ?

21

This is not helpful at all I need the answer.😡

41

To find the fraction of a year that the farmers farmed, we need to divide the number of months they farmed by the total number of months in a year.

In this case, the farmers farmed for nine months out of twelve. So, the fraction can be written as 9/12.

To reduce this fraction to its lowest terms, we need to find the greatest common divisor (GCD) of the numerator (9) and the denominator (12) and divide both numerator and denominator by it.

The prime factors of 9 are 3 * 3, and the prime factors of 12 are 2 * 2 * 3. The common prime factor is 3.

Dividing both the numerator and the denominator by 3, we get:

9 ÷ 3 = 3
12 ÷ 3 = 4

So, the fraction 9/12, when reduced to its lowest terms, becomes 3/4.

Therefore, the farmers farmed for 3/4 of the year.