At a museum child admission was $5.50 and adult admission is $9 on Monday twice as many adult tickets as child tickets were sold for a total sale of $611.00 how many child tickets were sold that day?
number of children tickets --- x
number of adult tickets ------ 2x
solve for x:
5.5x + 9(2x) = 611
Let's assume the number of child tickets sold is x.
Since twice as many adult tickets were sold, the number of adult tickets sold would be 2x.
The total revenue from child tickets would be 5.50 * x.
The total revenue from adult tickets would be 9 * 2x.
The total sale is given as $611, so we can set up the equation:
5.50x + 9(2x) = 611
Expanding the equation, we get:
5.50x + 18x = 611
Combining like terms, we have:
23.50x = 611
To solve for x, divide both sides of the equation by 23.50:
x = 611 / 23.50
Calculating the value of x, we get:
x ≈ 26.04
Since we cannot have a fraction of a ticket, we round down to the nearest whole number.
Therefore, approximately 26 child tickets were sold that day.
To solve this problem, let's set up the equations based on the given information:
Let's assume the number of child tickets sold was 'x'.
According to the information, the number of adult tickets sold was twice the number of child tickets sold, i.e. 2x.
Now, we'll calculate the total revenue from the ticket sales:
The revenue from child tickets = $5.50 * x
The revenue from adult tickets = $9.00 * 2x
Therefore, the total revenue from all the tickets sold is:
Total revenue = Revenue from child tickets + Revenue from adult tickets
Total revenue = ($5.50 * x) + ($9.00 * 2x)
The problem states that the total revenue is $611.00, so we can set up the equation:
$611.00 = ($5.50 * x) + ($9.00 * 2x)
Now we can solve this equation for x, which represents the number of child tickets sold.
First, distribute the multiplication:
$611.00 = $5.50x + $18.00x
Combine like terms:
$611.00 = $23.50x
Next, divide both sides of the equation by $23.50 to solve for x:
x = $611.00 / $23.50
Calculating this, we find that x ≈ 26.04
Since we can't sell fractional tickets, we need to round down to the nearest whole number.
Therefore, the number of child tickets sold was approximately 26.
So, on Monday, 26 child tickets were sold at the museum.