A calculator was dropped at an equation of d= 0.5*9.8t^2 + 5t

How long would it take for the calculator to hit the ground? HINT: SET THE EQUATION TO ZERO.

so, follow the hint

4.9t^2 + 5t = 0
t(4.9t+5)=0

a product is zero if either factor is zero.

Now, do you see a problem with your equation for d?
Hint: if t>0, d will never be 0.