3. Calculate the magnitude of the force required to cause an anterior dislocation of the glenohumeral joint given that he force has a lever arm of 52 cm, the maximum magnitude of the resistance force is 1080 N and the resistance force has a lever arm of 4.3 cm.
To calculate the magnitude of the force required to cause an anterior dislocation of the glenohumeral joint, we can use the principle of moments or torque. Torque is a measure of the tendency of a force to cause rotation around an axis.
In this case, we have two forces acting on the joint: the force required to cause dislocation and the resistance force preventing it. We are given the lever arms for both forces and the magnitude of the resistance force. To calculate the force required, we can set up an equation using the principle of moments.
The principle of moments states that the sum of the torques on an object is equal to zero in equilibrium. We can express this as:
(F × r) - (R × R) = 0
Where:
F is the force required to cause dislocation
r is the lever arm of the force F
R is the magnitude of the resistance force
R is the lever arm of the resistance force
Plugging in the given values, we get:
(F × 0.52 m) - (1080 N × 0.043 m) = 0
Simplifying the equation:
0.52F - 46.44 = 0
0.52F = 46.44
Dividing both sides by 0.52:
F = 46.44 / 0.52
F ≈ 89.31 N
Therefore, the magnitude of the force required to cause an anterior dislocation of the glenohumeral joint is approximately 89.31 Newtons.