for the reaction 2C2H2(g)=>C6H6(l) at 25 C, the standard enthalpy change is -631 kJ and the standard entropy change is -430 J/K. calculate the standard free energy change at 25 C. show all work

Help please!

See your post above.

To calculate the standard free energy change (ΔG°) at 25°C, you can use the equation:

ΔG° = ΔH° - TΔS°

Where:
ΔH° is the standard enthalpy change (-631 kJ)
ΔS° is the standard entropy change (-430 J/K)
T is the temperature in Kelvin (25°C = 298 K)

Let's substitute the given values into the equation:

ΔG° = (-631 kJ) - (298 K) * (-430 J/K)

Before calculating, let's convert the units to a consistent one (Joules) for easier calculation:

ΔH° = -631 kJ = -631,000 J
ΔS° = -430 J/K

Now calculate:

ΔG° = (-631,000 J) - (298 K) * (-430 J/K)
ΔG° = -631,000 J + 128,740 J
ΔG° = -502,260 J

Finally, we convert the result back to kilojoules:

ΔG° = -502,260 J = -502.26 kJ

Therefore, the standard free energy change at 25°C is -502.26 kJ.