How do I solve the following:
500ml .4M aluminum nitrate solution contains ______moles of aluminum ions and _______moles of nitrate ions.
I am helping my fiance and we don't know how to calculate this.
mols = M x L = 0.4M x 0.500L = 0.2mols Al(NO3)3 is what you have.
So you have 0.2 mols Al and 3 x 0.2 = 0.6 mols NO3^-
To solve this problem, you will need to use the concept of molarity and the given information.
Step 1: Understand the given information. We are given the volume of the aluminum nitrate solution (500 mL) and the molarity of the solution (0.4 M).
Step 2: Determine the number of moles of aluminum ions. The molarity (M) of a solution is defined as the number of moles of solute per liter of solvent. Since we are given the volume in milliliters, we need to convert it to liters by dividing it by 1000:
Volume of the solution = 500 mL = 500/1000 L = 0.5 L
Now we can calculate the moles of aluminum ions:
Moles of aluminum ions = Molarity × Volume in liters
Moles of aluminum ions = 0.4 M × 0.5 L
Moles of aluminum ions = 0.2 moles
So, the aluminum nitrate solution contains 0.2 moles of aluminum ions.
Step 3: Determine the number of moles of nitrate ions. Aluminum nitrate (Al(NO3)3) dissociates into one aluminum ion (Al³⁺) and three nitrate ions (NO3⁻). Therefore, the number of moles of nitrate ions is three times the number of moles of aluminum ions.
Moles of nitrate ions = 3 × Moles of aluminum ions
Moles of nitrate ions = 3 × 0.2 moles
Moles of nitrate ions = 0.6 moles
So, the aluminum nitrate solution contains 0.6 moles of nitrate ions.
Therefore, the answer to the given question is that the aluminum nitrate solution contains 0.2 moles of aluminum ions and 0.6 moles of nitrate ions.
To solve this problem, you need to understand the concept of molarity (M) and the relationship between molarity, moles, and volume.
Molarity (M) is defined as the number of moles of solute per liter of solution. In other words, it represents the concentration of a solute in a solution.
To determine the number of moles of a solute, you can use the formula:
moles = molarity × volume (in liters)
In this case, you are given the molarity (0.4M) and the volume (500ml) of the aluminum nitrate solution. However, before we can use this formula, we need to convert the volume from milliliters (ml) to liters (L) because the molarity is given in moles per liter.
To convert from milliliters to liters, you divide the volume by 1000:
Volume (in liters) = 500ml / 1000 = 0.5L
Now that we have the volume in liters, we can plug the numbers into the formula to calculate the number of moles of aluminum ions and nitrate ions.
For the moles of aluminum ions:
moles of aluminum ions = molarity × volume (in liters)
= 0.4M × 0.5L
Similarly, for the moles of nitrate ions:
moles of nitrate ions = molarity × volume (in liters)
= 0.4M × 0.5L
Now, you can solve these calculations using your calculator or by hand:
moles of aluminum ions = 0.4M × 0.5L = 0.2 moles
moles of nitrate ions = 0.4M × 0.5L = 0.2 moles
Therefore, the aluminum nitrate solution contains 0.2 moles of aluminum ions and 0.2 moles of nitrate ions.