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Find the exanct real number of sec^-1√2, w/out calculator.
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you know a 45-45-90 triangle has legs 1,1 and hypotenuse √2
and so, ...
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1) Find two values of o that satisfy the equation. Give your answers in degrees and radians. Do not use a calculator.
(a) sec o =
Top answer:
sec(x) = 1/cos(x). So all you need to do is find where cos(x) = 1/2 or 1/(-2).
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1) Find two values of Q that satisfy the equation. Give your answer is degrees and radians. Do not use a calculator.
a) sec Q = 2
Top answer:
To solve the equation sec(Q) = 2, we need to find the values of Q in both degrees and radians. The
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1) Find two values of Q that satisfy the equation. Give your answer is degrees and radians. Do not use a calculator.
a) sec Q = 2
Top answer:
I will do the second one. The first thing I do is to change the expression into one of the 3 basic
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Find the exact value of each expression(no calculator):
1) sin^2(30degrees) + 1/sec^2(20degrees) 2) sec(50degrees)*cos(50degrees)
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To find the exact value of each expression without using a calculator, we can utilize trigonometric
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how do you find the square root of any number with long division and not a calculator? I don't like calculator readings. They
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You echo what I think also. However, for square roots, it is a little more complicated (but not
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Given f '(x) = (x − 4)(4 − 2x), find the x-coordinate for the relative maximum on the graph of f(x).
a) 12 m/sec; 22 m/sec^2
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I think you have mixed two problems.
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Need to find the real number.
Someone performed a trade of 20,000 less than it made, this caused a negative trade balance. To
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To find the real number, let's analyze the given information step by step. 1. Someone performed a
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Use a calculator to determine angle x, rounded
to the nearest degree. a) csc x 1.25 b) sec x _ 12 7 c) cot x 3.1416 d) sec x 1.32
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a) To solve for angle x using the given equation csc x = 1.25, we need to take the inverse of the
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sec 7pi/4 without a calculator
Find the exact answer
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sec 7pi/4 = 1/cos(7π/4) 7π/4 is in quad IV, where the cosine is positive 7π/4 is π/4 away from
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Find the real-number root √−3.82 show your work
A 1.95 B -1,95 C infinite real number roots D no real numbers
Top answer:
The square root of a negative number is an imaginary number, not a real number. Therefore, there are
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