A volume of 122mL of argon, Ar, is collected at 50 degrees Celsius and 758 torr. What does this sample weigh?
To find the weight of the sample of argon, we need to use the ideal gas law equation:
PV = nRT
Where:
P = Pressure in atmospheres (atm)
V = Volume in liters (L)
n = Number of moles
R = Ideal gas constant = 0.0821 L.atm/mol.K
T = Temperature in Kelvin (K)
First, we convert the given volume from mL to L:
122 mL = 122/1000 = 0.122 L
Next, we convert the given temperature from degrees Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 50 + 273.15 = 323.15 K
Now, we can rearrange the ideal gas law equation to solve for n:
n = PV / RT
Substituting in the given values:
P = 758 torr = 758/760 atm (since 1 atm = 760 torr)
V = 0.122 L
R = 0.0821 L.atm/mol.K
T = 323.15 K
n = (758/760) * 0.122 / (0.0821 * 323.15)
n = 0.0998 moles
Finally, we can calculate the weight of the sample using the molar mass of argon, which is approximately 39.95 g/mol:
Weight = n * molar mass
Weight = 0.0998 mol * 39.95 g/mol
Weight ≈ 3.99 g
Therefore, the weight of the sample of argon is approximately 3.99 grams.
To find the weight of the sample of argon, you need to use the ideal gas law equation, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
First, convert the volume from mL to liters:
Volume = 122 mL = 122/1000 = 0.122 L
Next, convert the temperature from degrees Celsius to Kelvin:
Temperature in Kelvin = 50 degrees Celsius + 273.15 = 323.15 K
Now we have P = 758 torr, V = 0.122 L, and T = 323.15 K.
Using the ideal gas law equation, we can rearrange it to solve for n, the number of moles of gas:
n = PV / RT
The Ideal Gas Constant, R, is 0.0821 L.atm/mol.K.
n = (758 torr * 0.122 L) / (0.0821 L.atm/mol.K * 323.15 K)
Calculate the value of n.
Next, to find the weight of the sample of argon, you need to know the molar mass of argon, Ar, which is approximately 39.95 g/mol.
Finally, multiply the number of moles (n) by the molar mass (39.95 g/mol) to find the weight of the sample of argon.