a sample of gas occupies 500ml at STP. what volume will the gas occupy at 85.0 degrees Celsius
To calculate the volume of a gas at a specific temperature, you can use the combined gas law equation, which is a variation of the ideal gas law. The combined gas law equation is given as:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Where:
P1 and P2 are the initial and final pressures of the gas (measured in the same units, such as atm or Pa).
V1 and V2 are the initial and final volumes of the gas (measured in the same units, such as mL or L).
T1 and T2 are the initial and final temperatures of the gas (measured in Kelvin).
In this case, the initial temperature is at STP, which is equal to 273.15 Kelvin. The final temperature is given as 85.0 degrees Celsius. Therefore, we need to convert it to Kelvin by adding 273.15:
T2 = 85.0 + 273.15 = 358.15 Kelvin.
Since the gas is at STP, the initial pressure is 1 atmosphere (atm), which does not change. Therefore, we can rewrite the equation as:
(1 atm * V1) / (273.15 K) = (P2 * V2) / (358.15 K)
Solving for V2 (the final volume) in the equation, we get:
V2 = (P2 * V1 * 358.15 K) / (1 atm * 273.15 K)
Now, substitute the given initial volume (V1 = 500 mL = 0.5 L) and solve for V2 using the equation:
V2 = (P2 * 0.5 L * 358.15 K) / (1 atm * 273.15 K)
Since no information about the pressure (P2) is given, we cannot determine the exact volume at 85.0 degrees Celsius. However, you can calculate the final volume once you know the pressure at that temperature.
(V1/T1) = (V2/T2)
Remember T must be in kelvin.