Which ordered pair is a solution of the inequality?
y ¡Ý 4x ¨C 5
A(3, 4)
B(2, 1)
C(3, 0)
D(1, 1)
I think it is C?
correction - I think this is D
Not sure why it posted like that....
it's y> or equal to 4x-5.....
I think this is D...
not sure how you got B???
To determine which ordered pair is a solution of the inequality y ≥ 4x - 5, you need to substitute the x and y values of each option into the inequality and see if it holds true.
Let's check each option:
1. Option A: (3, 4)
Substitute x = 3 and y = 4 into the inequality:
4 ≥ 4(3) - 5
4 ≥ 12 - 5
4 ≥ 7
This inequality is false, so option A is not a solution.
2. Option B: (2, 1)
Substitute x = 2 and y = 1 into the inequality:
1 ≥ 4(2) - 5
1 ≥ 8 - 5
1 ≥ 3
This inequality is false, so option B is not a solution.
3. Option C: (3, 0)
Substitute x = 3 and y = 0 into the inequality:
0 ≥ 4(3) - 5
0 ≥ 12 - 5
0 ≥ 7
This inequality is false, so option C is not a solution.
4. Option D: (1, 1)
Substitute x = 1 and y = 1 into the inequality:
1 ≥ 4(1) - 5
1 ≥ 4 - 5
1 ≥ -1
This inequality is true, so option D is a solution.
Therefore, the correct answer is option D, (1, 1).
To determine if an ordered pair is a solution to an inequality, substitute the values of the ordered pair into the inequality and see if the resulting statement is true or false.
For the given inequality y ≥ 4x - 5:
Testing option A(3, 4):
Substitute x = 3 and y = 4 into the inequality:
4 ≥ 4(3) - 5
Simplifying the right side:
4 ≥ 12 - 5
4 ≥ 7
This statement is false, so A(3, 4) is not a solution.
Testing option B(2, 1):
Substitute x = 2 and y = 1:
1 ≥ 4(2) - 5
1 ≥ 8 - 5
1 ≥ 3
This statement is false, so B(2, 1) is not a solution.
Testing option C(3, 0):
Substitute x = 3 and y = 0:
0 ≥ 4(3) - 5
0 ≥ 12 - 5
0 ≥ 7
This statement is false, so C(3, 0) is not a solution either.
Testing option D(1, 1):
Substitute x = 1 and y = 1:
1 ≥ 4(1) - 5
1 ≥ 4 - 5
1 ≥ -1
This statement is true, so D(1, 1) is a solution.
Therefore, the correct answer is D(1, 1).