how many gallons would a hole 100ft deep by 6ft wide hold

What is the shape of this hole? Is 6 feet a diameter? If so,

V = πr^2h

d = 2r

one cubic foot = 7.48 gallons

I'll let you do the calculations.

To calculate the number of gallons that a hole can hold, we need to determine the volume of the hole first. The volume of a cylinder, such as a hole, can be calculated by multiplying the cross-sectional area of the hole by its height.

To find the cross-sectional area, we use the formula for the area of a circle: A = πr², where A is the area and r is the radius of the circle. Since the hole is given a width of 6ft, the radius would be half of that, which is 3ft.

Next, we calculate the cross-sectional area by substituting the values into the formula: A = π(3ft)² = 9π ft².

Finally, we multiply the cross-sectional area by the height of the hole, which is 100ft, to find the volume: V = 9π ft² × 100ft = 900π ft³.

Since we want the answer in gallons, we need to convert cubic feet to gallons. One US gallon is equivalent to approximately 7.48 cubic feet. Therefore, we can calculate the number of gallons by multiplying the volume in cubic feet by the conversion factor:

V in gallons = 900π ft³ × 7.48 gallons/ft³.

Now, let's calculate the result:

V in gallons = 900π ft³ × 7.48 gallons/ft³ ≈ 21238.3 gallons.

Therefore, a hole 100ft deep by 6ft wide would hold approximately 21238.3 gallons.