Calculate the pH resulting from the addition of the following:
50mL 0.1M KOH and 50mL 0.1M HBr
KOH + HBr ==> H2O + NaBr.
50 x 0.1 = 50 x 0.1 so this is at the exact equivalence point which means that the pH is determined by the hydrolysis of the NaBr salt.
Neither Na^+ nor Br^- is hydolyzed in H2O solution; therefore, the pH is not changed from neutral H2O so pH = 7.0