A solution is prepared by dissolving 75.0 grams of sucrose (C12H22O11) in enough water to produce 1.00L of solution. What is the molarity of this solution?
.219 M
Find the molar weight, divide the grams by the molar weight= moles Molarity=moles/liter
To find the molarity of the solution, we need to use the following formula:
Molarity (M) = moles of solute / volume of solution in liters
First, we need to convert the mass of the sucrose into moles. To do this, we can use the molecular weight of sucrose, which is (12 × 12) + (1 × 22) + (16 × 11) = 342 g/mol.
Number of moles of sucrose = mass of sucrose / molecular weight of sucrose
= 75.0 g / 342 g/mol
Now we need to calculate the volume of the solution in liters. Since the volume is given as 1.00 L, we can directly use this value.
Now we can substitute the values into the equation:
Molarity (M) = (75.0 g / 342 g/mol) / 1.00 L
Simplifying the expression:
Molarity (M) = 75.0 g / (342 g/mol × 1.00 L)
= 75.0 g / 342 g/mol
≈ 0.219 M
Therefore, the molarity of the solution is approximately 0.219 M.
To find the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). In this case, you are given the mass of the solute (75.0 grams) and the volume of the solution (1.00 L).
Step 1: Convert the mass of sucrose to moles.
To do this, you need to know the molar mass of sucrose (C12H22O11). The molar mass can be calculated by adding up the atomic masses of each element in the compound.
C12H22O11:
C: 12.01 g/mol x 12 = 144.12 g/mol
H: 1.01 g/mol x 22 = 22.22 g/mol
O: 16.00 g/mol x 11 = 176.00 g/mol
Now add up the masses of each element:
144.12 g/mol + 22.22 g/mol + 176.00 g/mol = 342.34 g/mol
Next, divide the mass of the solute (75.0 g) by the molar mass of sucrose:
75.0 g / 342.34 g/mol = 0.219 moles
Step 2: Calculate the molarity.
Molarity (M) is defined as the moles of solute divided by the volume of the solution in liters.
Molarity (M) = moles of solute / volume of solution (in L)
M = 0.219 moles / 1.00 L = 0.219 M
Therefore, the molarity of this solution is 0.219 M.