A boat is tied to a pier with a 25-foot rope so that the distance between the top of the pier and the top of the boat deck is 7 feet. If the water level s down 8 feet with the low tide , how much closer ( in feet) is the boat to the base of the pier? Assume the rope is always taut? Shows your work

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  1. high tide:
    x^2 + 7^2 = 25^2
    x^2 = 576
    x = 24

    low tide:
    x^2 + 15^2 = 25^
    x^2 = 400
    x = 20

    The distance change is 4 ft

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