(a) Construct a Lewis structure for O2 in which each atom achieves an octet of electrons. (Assign lone pairs where appropriate.)
i am using marvin sketch and don't know what i need to show
To construct a Lewis structure for O2, you need to follow these steps:
Step 1: Determine the total number of valence electrons for O2.
Since oxygen (O) is in Group 6A (Group 16) on the periodic table, it has 6 valence electrons. Since there are two oxygen atoms in O2, the total number of valence electrons is 2 × 6 = 12.
Step 2: Arrange the atoms in the molecule.
Oxygen molecules (O2) consist of two oxygen atoms bonded together. To represent this, draw the two oxygen atoms side by side.
Step 3: Connect the atoms with a double bond.
To achieve an octet of electrons for each oxygen atom, they need to share four electrons. This can be achieved by drawing a double bond between the two oxygen atoms. A double bond consists of two shared electron pairs.
Step 4: Assign lone pairs of electrons.
After the double bond is drawn, each oxygen atom should have six valence electrons. To complete the octet for each oxygen atom, assign two lone pairs of electrons on each atom. Lone pairs are represented by dots.
The final Lewis structure for O2 should look like this:
O = O
Each oxygen atom has an octet of electrons, i.e., 2 lone pairs and 2 shared electrons in a double bond.